In our class thought experiment isobarically boiling water w

In our class thought experiment isobarically boiling water, we saw that the liquid phase is almost incompressible. More precisely, the specific volume of the liquid at a given temperature doesn\'t change appreciably near the vapor pressure curve from the saturated liquid specific volume. In the absence of compressed liquid data, one approximates the the specific volume of a compressed liquid at a given T by V_f. What is the specific volume of water at 20degree C and 100 kPa? Check: The specific volume of R-134a at p = 970 kPa and T = 38degree C is approximately 0.0008657 m^3/kg

Solution

>> As, at P = 100 kPa ,

Seeing from Steam Table,

T_sat = 100°C

But, here T = 20°C is less than T_sat

>> At, saturation specific volume, v_f = 0.001043 m³/Kg

So, Specific Volume at Given State , v = 0.001043 m³/Kg ..... ANSWER....

Checking for R134a

At P = 970 kPa

Seeing from Property Table of R134a,

T_sat = 38. 24°C

So, our given state is almost at saturated liquid state

So, Specific Volume = v_f  = 0.0008657 m³/Kg...

Thus, it is true.....