Find the excluded values of x 32x 1 13212 Find the exclude

Find the excluded value(s) of x - 3/2x - 1 1321/2 Find the excluded value(s) of 5x/(x + 2) (x - 2) -2,2 2 -2 0,-2,2

Solution

As we know excluded values are the values which makes the denominator equal to zero.

Hence to find the excluded value we\'ll make denomintor equal to zero and find the value of x for which it becomes zero, that will be our excluded value.

1. 2x-1=0 => 2x=1 => x=1/2

So the excluded value is 1/2

2. (x+2)(x-2)=0

To make above equal to zero either of the bracket term can be zero or both.

so, either x+2=0 or x-2=0 or both are zero

x+2=0 => x=-2

x-2=0 => x=2

So the excluded values are 2,-2