A professional employee in a large corporation receives an a
Solution
Formulating the null and alternative hypotheses,
Ho: u = 38.9
Ha: u =/ 38.9
As we can see, this is a two tailed test.
Thus, getting the critical z, as alpha = 0.1 ,
alpha/2 = 0.05
zcrit = +/- 1.644853627
Getting the test statistic, as
X = sample mean = 30.1
uo = hypothesized mean = 38.9
n = sample size = 31
s = standard deviation = 19.4
Thus, z = (X - uo) * sqrt(n) / s = -2.525583835
Also, the p value is
p = 0.011550622
As P < 0.10, we reject Ho.
Thus,
OPTION A: The P value is less than the level of significance so the data are statistically significant. [ANSWER, A]
