The time to failure of a cathode ray tube has the following
The time to failure of a cathode ray tube has the following probability density function with a
mean failure rate 1/ = 1000:
f(t) = { e^-t t >= 0
Assume the cathode ray tube was functioning after 100 working hours. Find the probability,
that the cathode ray tube is still functioning after 300 working hours.
Solution
Time to failure T is exponential with parameter lemda = 0.001
P(t>300/t>100) =e-3/e-1
= 1/e^2
= 0.1353
