Characterization Mechanical Properties Figure 41 shows a ser
Characterization, Mechanical Properties. Figure 4.1 shows a series of SPM images for residual Berkovich indents in a 320 nm thick TiW film deposited on a [100] Si substrate. Calculate and plot the hardness versus depth curve using the 6 indents. Is the hardness constant? Explain why or why not. List any assumptions.
Solution
solution:
1)here we are using berkovich indentor for which semi angle is 65.3 degree and effective cone angle is 76.9 degree
2)projected area of berkovich indentor is obtain from
A=24.56h^2
3)here hardness is given by
H=P/A
4)here for TiW plate depth of indentation for .5 MN and 300 Mn are 33 nm and 1297 nm
hence hardness are
H1=.5*10^6/24.56*(33*10^-6)^2
H1=18.69 GPa
for P=300 MN
H6=7.21 GPA
3)hence load dpth curve is given by
P=a(h2-h1)^b
4)hence it is observe that value of GPA or hardness is not constant for each load because pile up effect is more if
hmax>320nm
5)hence hardness not constant but close to around 13 GPA for given material
![Characterization, Mechanical Properties. Figure 4.1 shows a series of SPM images for residual Berkovich indents in a 320 nm thick TiW film deposited on a [100] Characterization, Mechanical Properties. Figure 4.1 shows a series of SPM images for residual Berkovich indents in a 320 nm thick TiW film deposited on a [100]](/WebImages/3/characterization-mechanical-properties-figure-41-shows-a-ser-975805-1761500526-0.webp)