Determine the moment of inertia for the beams crosssectional

Determine the moment of inertia for the beam\'s cross-sectional area about the x axis. Express your answer to three significant figures and include the appropriate units.

Solution

Given that

a = 15 in

b = 10 in

c = 1 in

d = 5 in

I_xy = [ ( c / 2 ) ( b / 2 ) cb ] + { ( a / 2 ) ( c / 2 ) [ ( a - 2c ) c ] } + dc { [ a - ( c / 2 ) ] [ d / 2 ]

I_xy = [ ( 1 / 2 ) ( 10 / 2 ) 10 ] + { ( 15 / 2 ) ( 1 / 2 ) ( 15 - 2 ) } + 5 [ 15 - ( 1 / 2 ) ] [ 5 / 2 ]

I_xy = 25 + 48.75 + 68.75

I_xy = 142.5 in⁴

I have so many times. may e the answer given was wrong or some vales are wrong check once.