Homework SourseHELP POINTS WILL BE GIVEN SHOW ALL THE WORK THANKS The circu
HELP!! POINTS WILL BE GIVEN!! SHOW ALL THE WORK, THANKS.
The circuit below is in steady state
A. Calculate the voltage across the capacitor Vc and the current through the inductor iL
B. Calculate the energy stored in the capacitor.
C. Calculate the energy stored in the inductor.
Solution
for DC Source capacitor is open circuit and inductor is short circuit(in steady state)
current through the inductor = 24/(4+2) = 4mA
energy stored in the inductor = 1/2*L*I^2 = 0.5*2*16*10^(-6) = 16 ujoul
voltage across the capacitor = 2*4 = 8V
energy stored in the capacitor = 1/2*C* V^2 = 0.5*0.1*64 = 3.2 joul
