A rigid tank of volume 075m3 b initially evacuated A hole de

A rigid tank of volume 0.75m^3 b initially evacuated A hole develops in the wall, and air from the surrounding at 1 bar, 25degreeC flows in until the pressure in the tank reaches 1 bar, Heat transfer between the contents of the tank and the surrounding is negligible. Determine the final temperature of the tank, in degreeC.

Solution

NO heat is transfered during the process

therefore work done   = change in potential energy

Work done = 1 * 10^5 * 0.75   = 75000 J

Change in potential Energy   = m * Cv * (Tf - Ti)

                                          = 1.225 * 0.75 * 718 * (Tf - 298)   = 659.6625 (Tf - Ti)

Tf - 298 = 75000 / 659.6625

Tf = 411.6945 K