Set up tables and verify each identity i tanA cotA sin2A asi

Set up tables and verify each identity.

i. tanA cotA sin2A asin (B0) bcos where C arctan. a 0 sin (B0 C

Solution

i.) taking LHS

tan A + cot A,

we know tan A=sin A/cosA and cot A= cosA/sin A

so,

sinA/cosA+cosA/sinA= (sin^2 A+cos^2 A)/(sinA cosA)

we know sin^2 A+cos^2 A=1

so,

1/sinA cosA= 2/2sinA cos A= 2/sin2A because sin2A=2 sinA cosA

hence LHS=RHS hence proved