1 Passing through 73 and perpendicular to the line whose equ

1) Passing through (7,-3) and perpendicular to the line whose equation is Y = 1/3x+5

Write an equation for the line in point-slope form

Write an equation for the line in slope-intercept form

2) Passing through (-3,-4) and perpendicular to the line whose equation is Y = -4x+4

Write an equation for the line in point-slope form

Write an equation for the line in slope-intercept form

3) Use the given conditions to write an equation for the line in point-slope form and slope-intercept form.

Slope = -7 passing through (-1,-1)

4) Write the point-slope form of the line satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation.

Slope = 4 passing through (-3,9)

5)Write the point-slope form of the line\'s equation satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation.

Slope = 4 passing through (2,7)

Solution

1) Passing through (7,-3) and perpendicular to the line whose equation is Y = 1/3x+5

slope of line = -3

slope intercept form of equation : y=mx +c where m is slope and we have to find, c , y intercept

y= -3x +c

-3 = -21 +c ---> c= 18

y = -3x +18 (slope intercept form)

Now , point slope form: y -y1 = m( x- x1) where (x1, y1) is one point on line

y +3 = -3(x -7)

2) Passing through (-3,-4) and perpendicular to the line whose equation is Y = -4x+4

slope of line passing though = 1/4

slope intercept form of equation : y=mx +c where m is slope and we have to find, c , y intercept

y= x/4 +c

-4 = -3/4 +c ---> c = -4 +3/4 = -13/4

y = x/4 -13/4

Now , point slope form: y -y1 = m( x- x1) where (x1, y1) is one point on line

y +4 = (x +3)/4

3)

write an equation for the line in point-slope form and slope-intercept form.

Slope = -7 passing through (-1,-1)

Point-slope form : y -y1 = m( x-x1)

y +1 = -7(x+1)

Slope intercept form : y +1 = -7x -7

y = -7x -8