A3 y14 x 1 A3 11254 SolutionFirts we find the triangle form

Solution

Firts we find the triangle form by the two lines and y axis----A1

Then we find the are of sector of circle formed by line y = x ----A2

Shaded Area A3 = A2 -A1

A1: point of intersection of two lines :y =x ; y = -x/4 +1

x = -x/4 +1 ----> 5x/4 =1

x = 4/5 ; y = 4/5

( 4/5 , 4/5)

other points of triangle ( 0, 0) and (0,1)

Now find are of triangle using Area = sqrt(s(s-a)(s-b)(s-c)) where s = (a+b+c)/2

So, A1 = 0.4 unitsq

Now A2 = pi*r^2(45/360) = pi(*6)^2*(0.125) = 14.14 unitsq

A3 = A2- A1 = 14.14 -0.4 = 13.74 squnits