A point charge q1 32 C is located at the origin of a coordi

A point charge q₁ = -3.2 C is located at the origin of a co-ordinate system. Another point charge q₂ = 5.9 C is located along the x-axis at a distance x₂ = 6.6 cm from q₁.

the value of the x-component of the force that q₁ exerts on q_{2 is -38.92.}

Charge q₂ is now displaced a distance y₂ = 3.7 cm in the positive y-direction. What is the new value for the x-component of the force that q₁ exerts on q₂? (C)?

How would you change q₁ (keeping q₂ and q₃ fixed) in order to make the net force on q₂ equal to zero?

--Increase its magnitude and change its sign

--Decrease its magnitude and change its sign

--Increase its magnitude and keep its sign the same

--Decrease its magnitude and keep its sign the same

-- There is no change you can make to q₁ that will result in the fet force on q₂ being equal to zero.

How would you change q₃ (keeping q₁ and q₂ fixed) in order to make the net force on q₂ equal to zero?

--Increase its magnitude and change its sign

--Decrease its magnitude and change its sign

--Increase its magnitude and keep its sign the same

--Decrease its magnitude and keep its sign the same

-- There is no change you can make to q₃ that will result in the fet force on q₂ being equal to zero.

Solution

The initial x-component of the force between q1 and q2 is net force , since the only component is x-componenet

i.e                  Fx = F ,

when the charge q2 is displaced 3.7 cm in y direction , let the angle made by the line joining the two charges with x axis is q

          tan (q) = 3.7 cm / 6.6 cm

                 q = 29.275.

The new x- component of the force between q1 and q2

              F´x = Fx cos(q) = -38.92 cos(29.257) = -33.955