Find the domain of the function yLn4xy1Solutionperhaps you m

Solution

perhaps you mean
f(x,y)=ln(4x-y+1)
because y=ln(4x-y+1) is not a function

The logarithm is defined only for positive numbers
So we need to have 4x-y+1>0
So the domain of f is the set of pairs (x,y) such that 4x-y+1
In set notation
D={(x,y) in R²|4x-y+1>0}