In a population of pitcher plants 200 individuals are sample

In a population of pitcher plants, 200 individuals are sampled for variation at a locus. Sixteen are heterozygous for the X1 allele, and four are homozygous for it. What is the frequency of the X1 allele?

0.04

0.06

0.08

0.12

0.16


I need explanation and calculations please

Solution

Four out of 200 are homozygous for the allele; i.e. 4/200 = 0.02 = frequency of X1 genotype = q^2

2pq = frequency of heterozygous genotype = 16/200 = 0.08

Frequency of X1 allele = 0.02 + 1/2* 0.08 = 0.06 (correct answer)