Can anyone solve this problem Find sin 2x cos 2x tan 2x if

Can anyone solve this problem? Find sin 2x, cos 2x , tan 2x if tan x= 4/3 and x terminates in QI

tan x= 4/3 and x terminates in QI

sinx = 4/5 ; cosx = 3/5

i) sin2x = 2sinxcosx = 2(4/5)(3/5) = 24/25

ii) cos2x = 2cos^2x -1 = 2(3/5)^2 -1

= 18/25 -1 = -7/25

iii) tan2x = sin2x/cos2x =24/25 / -7/25 = -24/7