The solutions in the arms of a Utube are separated at the bo

The solutions in the arms of a U-tube are separated at the bottom of the tube by a selectively permeable membrane. The membrane is permeable to sodium chloride but not to glucose. Side A is filled with a solution of 0.4 mols of glucose and 0.5 mols of sodium chloride (NaCl), and side B is filled with a solution containing 0.8 mols of glucose and 0.4 mols of sodium chloride. Initially, the volume in both arms is the same. Initially at the start of the experiment, which of the following is true? side A is hypertonic to side B side A is hypotonic to side B side A is hypertonic to side B with respect to glucose side A is hypotonic to side B with respect to NaCl After diffusion and equilibrium: How many mols of glucose are on side A?_____ side B?_____ How many mols of NaCl are on side A?_____ side B?_____ If you examine side A after three days you should find_____. a decrease in the number of mols of NaCl and glucose and an increase in the water level a decrease in the number of mols of NaCl and a decrease in the water level a decrease in the number of mols of NaCl, an increase in water level, and no change in the number of mols of glucose

Solution

Ans A. NaCl is more hypertonic as compared to glucose as a result of which greater the concentration of NaCl would lead to increase in osmotic pressure and which in turn would lead to increase in its tonicity. Hence the correct option would be option A, side A is hypertonic to side B.

Ans B. As the membrane is impermeable to glucose the concentration of glucose won\'t change on both sides. Hence the concentration of glucose on side A would be 0.4 mols and that on side B would be 0.8 mols. On the contrary the diffusion of Nacl would take place and at equillibrium condition the concentration of Nacl would be equal on both sides, hence the concentration on both the sides would be 0.45 mols.

Ans C. The salt concentration is higher on side A, which would draw most of the water molecules towards itself leading to increase in the water level and due to equillibrium condition the salt concentration on side A would be reduced to some extent. The membrane is impermeable to glucose hence its concentration wont change. Therefore the correct option is option C.