ording to the relation Problem 2 The horizontal rod OA rotat

ording to the relation Problem 2: The horizontal rod OA rotates about a vertical shaft acc 6-20r, where è and r are held by a cord with a breaking strength of 18 N. Neglecting friction, determine, Ii after the cord breaks, (a) the relative acceleration of the collar with respect to the magnitude of the horizontal force exerted on the collar by the rod. (20 points) expressed in rad/s and seconds, respectively. A 200-g collar B is rod, (b) the 0.5 m

Solution

. = 20t

mb = 0.200kg

no friction Tmax = 18

find aB/rca = r.. Force exerted on the collar by rod (F0)

d2/dt2 = 20 rad/s^2

Fr = mar

18 = 0.200(0.5)(d/dt)^2

d/dt = 13.42

aB/rod = r(.)^2 = 0.5 * 13.42^2 = 90m/s^2

F = ma = 0.200*0.5*20 = 2N