Assume that a randomly selected subject is given a bone dens

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between -2.17 and 3.62 and draw a sketch of the region. Sketch the region. Choose the correct graph below. The probability is _________. (Round to four decimal places as needed.) Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per minute. Answer the following questions. What are the values of the mean and standard deviation after converting all pulse rates of women to z scores using z = (x - Mu) / sigma Mu = _________ sigma = _________ The original pulse rates are measure with units of \"beats per minute\". What are the units of the corresponding z scores Choose the correct choice below. The z scores are measured with units of \"minutes per beat.\" The z scores are measured with units of \"beats.\" The z scores are measured with units of \"beats per minute.\" The z scores are numbers without units of measurement.

Solution

16.

The correct figure is OPTION A, as it should only shade batween -2.17 (left of the mean) and 3.62 (right of the mean.) [option A]

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z1 = lower z score =    -2.17      
z2 = upper z score =     3.62      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.015003423      
P(z < z2) =    0.999852698      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.984849276 = 0.9848 [ANSWER]

If you use tables in your class instead of technology, please answer 0.9849.

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