Homework SourseSolve the equation below for all the solutions 02pi Answer i
Solve the equation below for all the solutions [0,2pi). Answer in radians
sin^2x-cos^2x=1
Solution
sin2x - cos2x = 1
[ from sin2x+ cos2x =1, sin2x = 1- cos2x]
1-cos2x - cos2x = 1
1- 2 cos2x = 1
2*cos2x = 0
cos2x = 0
cos x = 0
cos x = cos ( n*pi/2) where n = 1,3 lies in given range
x = n* pi/2
ie x = Pi/2, 3*pi/2
![Solve the equation below for all the solutions [0,2pi). Answer in radians sin^2x-cos^2x=1Solutionsin2x - cos2x = 1 [ from sin2x+ cos2x =1, sin2x = 1- cos2x] 1-c](/WebImages/3/solve-the-equation-below-for-all-the-solutions-02pi-answer-i-977088-1761501282-0.webp "Solve the equation below for all the solutions [0,2pi). Answer in radians sin^2x-cos^2x=1Solutionsin2x - cos2x = 1 [ from sin2x+ cos2x =1, sin2x = 1- cos2x] 1-c")
