Flow of gases at piping systems are often metered by chokedf
Solution
Mass flow rate m = f(A, p, T, R, Cp)
Dimensions of m = [MT-1]
Dimensions of area A = [L2]
Dimensions of pressure p = [ML-1T-2]
Dimensions of Temperature = [theta]
Dimensions of R and Cp = [L-2T-2theta-1]
There are 6 variables and 4 dimensions. Hence, we can have 6-4 = 2 dimensionless variables. Taking A, p, T, R as repeating variables we have,
Pi1 = [L2]a1 [ML-1T-2]b1 [theta]c1 [L-2T-2theta-1]d1 [MT-1]
Pi2 = [L2]a2 [ML-1T-2]b2 [theta]c2 [L-2T-2theta-1]d2 [L-2T-2theta-1]
The expression for Pi1 gives
b1 + 1 = 0
2*a1 - b1 - 2*d1 = 0
-2*b1 - 2*d1 - 1 = 0
c1 - d1 = 0
Solving, a = 0, b = -1, c = 1/2, d = 1/2
or Pi1 = A0 * P-1 * T1/2 R1/2 m
or Pi1 = m* sqrt (RT) / P
The expression for Pi2 gives
b2 = 0
2*a2 - b2 - 2*d2 - 2 = 0
-2*b2 - 2*d2 - 2 = 0
c2 - d2 - 1 = 0
Solving, a2 = 0, b2 = 0, c2 = 0, d2 = -1
or Pi2 = A0 * P0 * T0 R-1 Cp
or Pi2 = Cp / R
