Suppose the student in Figure 1 is 58 kg and the board being
Solution
call L the force exerted by the left support (and this will also be the reading on the left scale), and R the force exerted by the right support
these two supports must balance the weight of the person and the board, so
L+R=(58+12) g = 686N -------------------(1)
the board is also in rotational equilibrium, so all the torques sum to zero; let\'s sum torques around the left support, this means the lever arm of the force at L is zero so its torque is zero
torque due to weight of board = 12*g*1 =117.6Nm(clockwise)
torque due to weight of person=58*g*1.5=852.6N(clockwise)
torque due to force at R= R x 2m (counterclockwise)
so the torque at R equals the sum of the other two torques
2R=117.6Nm+ 852.6Nm
2R=970.2Nm
R=485.1N (49.5kg)
so L=200.9N (20.4kg) ( from eq (1)
