In a population at HardyWeinberg equilibrium the frequency o

In a population at Hardy-Weinberg equilibrium, the frequency of the a allele is 0.60. What is the frequency of individuals heterozygous for the A gene? None of the above This cannot be answered without more information.

Solution

The answer is C) 0.48

FIND THE BELOW EXPLANATION

A + a = 1
a = 0.60.
A = 1- a; = 1- 0.60 = 0.40

Aa = 2 X 0.60 X 0.40 = 0.48