1 Let xnn and ynn be Cauchy sequences Prove that xn ynn is
1. Let (xn)n and (yn)n be Cauchy sequences. Prove that (xn + yn)n is Cauchy.
2. Suppose that (xn)n is a Cauchy sequence of integers. Prove that there exists an
N N such that for every n > N xn = xN.
Solution
1.Let {xn} and {yn} be Cauchy.
Then for any > 0 there exists N1 N such that for any n, m N1, |xn xm| < 2 ,
and there exists N2 N such that for any n, m N2, |yn ym| < 2 .
Let N = max(N1, N2).
Then for any n, m N, |(xn + yn) (xm + ym)| = |(xn xm) + (yn ym)| |xn xm| + |yn ym| < 2 + 2 = . Thus {xn + yn} is Cauchy.
