A displacement vector D is given as 400 m long at an angle o

A displacement vector D is given as 40.0 m long at an angle of 60.0 degree t NORTH of CAST The D. component and the D, component of the vector are The graph shows the speedometer readme of a car as it comes to a stop alone a straight

Solution

22)

D = 40*(cos60 i + sin60 j)

So,

Dx = 40*cos(60 deg) = +20 m

and

Dy = 40*sin(60 deg) = +34.6 m

23)

Distance moved = area under the curve

= 20*4 + 0.5*20*(12-4)

= 160 m

24)

Graphically,

the distance traveled = area inder the curve from t=9s to t=13s

= 0.5*(13-9)*40

= 80 m <--------answer

25)

s1 = 5j <---- j = unit vector along +y axis(NORTH)

s2 = 5i <-------- i = unit vector along +x axis

s3 = 2 j

So, Snet = s1 + s2 + s3 = 5j + 5i + 2j

= 5i + 7j

So, magnitude of displacement = sqrt(5^2 +7^2) = 8.6 m <--------answer