Q1 Consider a 128 bytes of memory and a direct mapped cache

Q1 Consider a 128 bytes of memory, and a direct mapped cache that has eight blocks with 8 bytes per block. Assume memory is byte addressable. What the size of cache is in bits including the space for valid and tag information?

Solution

when Memory = 128 bytes,

blocks = 8 bytes

then the size of cache is

8*8*8 = 512 bits of cache