2 kg of air initially at 320 K undergoes a process that chan

2 kg of air initially at 320 K undergoes a process that changes its pressure from 1 bar to 3 bars such that its internal energy increases by 72,000J. Its final temperature is.

The ideal gas equation

PV = n R T

at constant volume

P1 / p2 = T1 / T2

T2 = P2 T1 / P1

= (3 bars ) ( 320 K ) / ( 1 bar )

=960 K

2 kg of air initially at 320 K undergoes a process that changes its pressure from 1 bar to 3 bars such that its internal energy increases by 72,000J. Its final

2 kg of air initially at 320 K undergoes a process that chan

Solution

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