For the circuit shown what is the percent error in the curre

For the circuit shown, what is the percent error in the current calculated for the assumption of ideal and practical diode behavior? Assume V=3.3 Volts and R=470 Ohms. 30.43% 21.21% 26.92 % 23.33%

Solution

The Diode in forward biased, so idealy it muts be short circuited, that is the voltage drop across didoe is zero

So the current in loop

I=3.3/470=7.02mA

But in ptractical didod the dideo will drop cutin voltage=0.7V

if we consider this

I=V-0.7/R=3.3-0.7/470=5.53mA

error=ideal-practical/ideal=7.02-5.53/7.02=21.21%