Homework SourseComplete the following frequency table Show work Im thinking
Complete the following frequency table. Show work.
I\'m thinking that the missing freqiency is 12 and the relative frequency would be 3/8 = .0375. I\'m just having a hard time showing the math on how that\'s calculated. Please let me know if that is a correct solution and if so, what math/formula is needed to get to it. Thanks
| Test Score Interval | Frequency | Relative Frequency |
| 40-49 | 1 | 1/32 = 0.03125 |
| 50-59 | 2 | 1/16 = 0.0625 |
| 60-69 | 5 | 5/32 = 0.15625 |
| 70-79 | ||
| 80-89 | 8 | 1/4 = 0.25 |
| 90-100 | 4 | 1/8 = 0.125 |
Solution
Yes, the missing frequency is 12. From first row, 1/32 = 0.03215, which means that sum of frequencies is 32
This means that the missing frequency is 32-1-2-5-8-4 = 12
And missing relative frequency is 12/32 = 0.375
