If Samantha and Logan can do their paper route together in 4

If Samantha and Logan can do their paper route together in 45 minutes, how many hours would it take each of them to it alone, given that Samantha is three times as fast as Logan?

Solution

Let time taken by Samantha to do it alone be T hours.

Then as per the information given in the question, time taken by Logan to do it alone be 3T hours as Samantha is 3 times as faster as logan.

Therefore, we can write it as:

1/T + 1/3T = 1/45

(3 + 1)/ 3T = 1/45

4/3T = 1/45

3T/4 = 45

T = 45*4/3

T = 60 minutes

Therefore, time taken by Samantha alone be 60 minutes

and time taken by Logan alone be 3*60 = 180 minutes