Find second partial derivatives Zxx Zxy Zyx and Zyy for z
Find second partial derivatives (Zxx, Zxy = Zyx, and Zyy) for z = (X^2 + y^2)^10. Please show steps as I have the correct answer. Thanks!
Solution
z=(x^2+y^2)^10
Zx=10*(x^2+y^2)^9 *(2*x)=20*x*((x^2+y^2)^9)
Zy=10*(x^2+y^2)^9 *(2*y)=20*y*((x^2+y^2)^9)
Zxx=20*x*9*(x^2+y^2)^8 *(2*x)=360*x2*((x^2+y^2)^8)
Zxy=20*x*((x^2+y^2)^8)*9*2*y=360*x*y*((x^2+y^2)^8)
Zyy=20*y*((x^2+y^2)^8)*9*2*y=360*y2*((x^2+y^2)^8)
