need help pls How long will it take a sample of radioactive
need help pls
Solution
the given expression is A(t) = 750 e^-0.144t
the initial amount is at t =0
A(0) = 750 e^0
=750
now we have to find the time to take 750/2
750/2 = 750 e^-0.144t
1/2 = e^-0.144t
apply ln to each side
ln(1/2) = ln(e^-0.144t)
-0.693 = -0.144t
0.144t =0.693
t = 0.693/0.144
t = 4.81 years
so Option D) is correct
