A local car dealer wants to design its inventory system to m
Solution
Assignment of Random numbers to daily demand per day:
Table 1
Demand per day
Probability
Cumulative
Probability
Interval of Random
Numbers
0 car
0.20
0.20
01 through 20
1 car
0.30
0.50
21 through 50
2 car
0.30
0.80
51 through 80
3 car
0.20
0.100
81 through 00
Assignment of Random numbers to days to receive an order:
Table 2
Days to receive an order
Probability
Cumulative
Probability
Interval of Random
Numbers
3 Days
0.40
0.40
01 through 40
5 Days
0.60
1.00
41 through 00
Day
Random Number
Demand per day
IOH
CLS
CPO
Random Number
Days to receive an order
1
03
0 car
225
0
0
2
80
2 car
223
1200
3
37
1 car
222
600
4
99
3 car
219
1800
5
19
0 car
6
11
0 car
7
68
2 car
217
1200
8
43
1 car
216
600
9
80
2 car
214
1200
10
22
1 car
213
600
11
13
1 car
212
600
12
19
1 car
211
600
| Table 1 | |||
| Demand per day | Probability | Cumulative Probability | Interval of Random Numbers |
| 0 car | 0.20 | 0.20 | 01 through 20 |
| 1 car | 0.30 | 0.50 | 21 through 50 |
| 2 car | 0.30 | 0.80 | 51 through 80 |
| 3 car | 0.20 | 0.100 | 81 through 00 |



