Solve the linear programming problem by the method of corner
Solve the linear programming problem by the method of corners. Maximize P = 3x + 7y subject to 2x + y lessthan equal 16 2x + 3y lessthan equal 24 y lessthan equal 5 x greaterthan equal 0, y greaterthan equal 0 (x, y) = ( The maximum is P = at ).
Solution
Feasible region:
Corner points are:
(0, 0) (0, 5) (8, 0) (4.5, 5) (6, 4)
Plug each corner point into profit function:
Corner point (x, y)
Therefore, profit is maximum at a corner point (4.5, 5)
Thus, (x, y) = (4.5, 5)
P = $48.5
| Corner point (x, y) | P = 3x + 7y | Profit (P) |
| (0, 0) | P = 3*0 + 7*0 | P = 0 |
| (0, 5) | P = 3*0 + 7*5 | P = 35 |
| (8, 0) | P = 3*8 + 7*0 | P = 24 |
| (4.5, 5) | P = 3*4.5 + 7*5 | P = 48.5 |
| (6, 4) | P = 3*6 + 7*4 | P = 46 |
