simplify ft2 3 when fx 4xsqr3xSolutionThe question is asking

simplify f(-t^2 +3) when f(x)= 4x[sqr(3-x)]

Solution

The question is asking you to substitute the \"x\" in the equation with \"(-t2+3).
This gives you:
f(-t2+3)=4*(-t2+3)*sqrt(3-(-t2+3))
Simplify by using distribution.
So,
4*(-t2+3)=-4t2+(4*3)=-4t2+12
And,
3-(-t2+3)=3+t2-3=(3-3)+t2=0+t2=t2
REMEMBER that a negative times a negative equals a positive (-1*-t2=t2)
Now you have:
f(-t2+3)=(-4t2+12)(sqrt(t2)
You know that:
(sqrt(t2)=t
So,
f(-t2+3)=(-4t2+12)t
Distribute the \"t\" through the parenthesis