1 pt Find a formula for the polynomial f r of least degree t

(1 pt) Find a formula for the polynomial f (r) of least degree that passes through the points (-4,0), (3,0), and (0, 1). f(x) = .nd (01)

Solution

1) y = (x-8)(x+5)

X intercept: y =0 gives x= 8, -5

Y interecpt: plug x=0; y = -40

when x--->+ infinty ; y--->+ infinity

when x--->- infinty ; y---> + infinity

2) y = (x-1)^2(x-6)

X intercept: plug y=0 ; x= 1,1, 6

Y intercept : plug x=0 ; y= -6

when x--->+ infinty ; y--->+ infinity

when x--->- infinty ; y--->- infinity

3) y = (x-1)^2(x-6)

X intercept: x1 = 1, x2=1, x3=6

Y intercept : plug x=0

y = -6

when x--->+ infinty ; y--->+ infinity

when x--->- infinty ; y---> - infinity