Consider the following graph of a transformation of a trigon

Consider the following graph of a transformation of a trigonometric function. Is the function even, odd, or neither even nor odd? State the period. Which of the following functions corresponds to the graph? f(x) = -4cos(x)-2 f(x) = -4cos(2x)-2 f(x) = 4 sin(x) - 2 f(x) = 4 sin(x) -2

Solution

(a)

Since the given graph is not symmetric about the y-axis therefore the function will be \"neither odd nor even

function.\"

One complete cycle complete in the time period of \"2pi\" , therefore the period is \"2pi\".

(c)

So the function is

f(x)=4 sin (x)-2 becuase it is neithe odd nor even and at x=0,the this function is \"y=-2\".