Calculate following probabilities area under the curse for t

Calculate following probabilities (area under the curse) for the standard normal variable, z

Solution

A)

Using a table/technology, the left tailed area of this is          
          
P(z <   1.01   ) =    0.843752355 [ANSWER]

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b)

z1 = lower z score =    0      
z2 = upper z score =     2.5      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.5      
P(z < z2) =    0.993790335      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.493790335   [ANSWER]

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c)

The area of the whole normal curve is = 1. [ANSWER]

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d)

z1 = lower z score =    -1.25      
z2 = upper z score =     3.19      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.105649774      
P(z < z2) =    0.999288636      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.893638862   [ANSWER]

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e)

Using a table/technology, the left tailed area of this is          
          
P(z <   -0.44   ) =    0.329968554 [ANSWER]