What percentage of the computers having an MTBF of 10000 h w

Solution

Mean time between failures = 10000 hours

Or we can convert this into Poisson as mean time for failure = 10000 hours

i.e. no of failures of computer in 10000 hours on an average = 1

Required prob =

P(X=1) = 0.3679

Hence 36.79% of the computers can be expected to run 10000 hours without failures