5 Consider the linear model logyt Beta0 xtBeta logyt1 ut
5. Consider the linear model log(yt) = Beta0 + xtBeta + log(yt1) + ut where E[ut|xt,yt1] = 0. Show that you obtain the same value of Beta whether you use lagged y (i.e., log(yt1)) or growth in y (i.e., log(yt)log(yt1)) as the dependent variable.
Solution
E[ut|xt,yt1] = 0 where t=0,1,2....
that means the error in any given period does not correlated with explanatory variables in any time periods and this also implies that x is contemporaneously exogenous.
From the above we can see that x is not constant and or a linear combination of others.
Therefore we can say that we will obtain same value of B.
![5. Consider the linear model log(yt) = Beta0 + xtBeta + log(yt1) + ut where E[ut|xt,yt1] = 0. Show that you obtain the same value of Beta whether you use lagged 5. Consider the linear model log(yt) = Beta0 + xtBeta + log(yt1) + ut where E[ut|xt,yt1] = 0. Show that you obtain the same value of Beta whether you use lagged](/WebImages/4/5-consider-the-linear-model-logyt-beta0-xtbeta-logyt1-ut-979053-1761502457-0.webp)