find the minimum sample size needed the estimate u c98s93 e

find the minimum sample size needed the estimate u c=.98,s=9.3, e= 1

Solution

Note that      
      
n = z(alpha/2)^2 s^2 / E^2      
      
where      
      
alpha/2 = (1 - confidence level)/2 =    0.01  
      
Using a table/technology,      
      
z(alpha/2) =    2.326347874  
      
Also,      
      
s = sample standard deviation =    9.3  
E = margin of error =    1  
      
Thus,      
      
n =    468.0747493  
      
Rounding up,      
      
n =    469   [ANSWER]