A geneticist Dr O Sophila discovers a new mutation that caus
Solution
Answer:
3.1)
Spastic (recessive) = s; Nonspastic (dominant)=s+
Vestigial wings (recessive)= v; Normal wings(dominant) = V
ssVV (spastic fly) x s+ s+ vv (Vestigial wings)-----P
sV s+v----------------------------gametes
s+sVv (nonspastic, normal wing)---------F1
F1 X ssvv------------Test cross.
During test cross, all the progeny should be in equal proportion, but it is not the case. So the genes were linked.
3.2).
F1 phenotype= nonspastic, normal wing
Genotyope: s+sVv
Recessive allele of one gene and dominant allele of the other gene present on the same chromosome, so the configuration of the genes is trans configuration.
3.3).
The recombinant phenotypes of F2 files are= spastic with vestigial wings and nonspastic with normal wings
3.4).
spastic with normal wings = ss Vv
Nonspastic with vestigial wings = s+svv
Spastic with vestigial wings = ssvv
Nonspastic with normal wings= s+sVv
3.5).
%Recombinant frequency = map distance (map units)
Recombinat frequency = (total number of recombinants / Total progeny)100
= 97+99 = (196/650)100 = 30.15%
The genetic distance between the v and s genes is 30.15 map units

