Suppose sin thetasqrt23 where theta terminates in Q2 Find si
Suppose sin theta=sqrt(2)/3 where theta terminates in Q2. Find sin(2theta)
Suppose sin theta=sqrt(2)/3 where theta terminates in Q2. Find sin(2theta)
Solution
given sin=(2)/3
in Q2 => cos is negative
adjacent side =[32-(2)2] =7
cos=-(7)/3
sin2=2sincos
sin2=2((2)/3)(-(7)/3)
sin2=-(214)/9
