The heights in cm of six basketball players are listed below

The heights (in cm) of six basketball players are listed below 198 192 207 201 212 196 Find the mean and the standard deviation.

Solution

1) Mean is the average of all the heights

= 198 + 192 +207 +201 +212 +196 /6 = 201

Variance = average of squares of the deviation from mean

= (198-201)^2 + (192-201)^2+(207-201)^2 + (201-201)^2 + (212-201)^2 + (196-201)^2/6

= 9 + 81 + 36 + 0 + 121 + 25/6

= 272/6

Standard deviation = sqrt variance = 6.733