A thin wire of density pxyyx2 has the shape of a parabola yx
A thin wire of density p(x,y)=y-x+2 has the shape of a parabola, y=x^2 from (-2,4) to (0,0). Set-up an integral to find the mass of the wire.
Solution
Data.
(x,y)= y-x+2
y = x2 (keep in mind for replacing)
boundaries are;
from (-2,4) to (0,0)
--
Answer.
Density mass integral is given by:
m = c (x,y) ds
-200x2 (y-x+2) dydx
-20 [y2/2 - xy + 2y]0x2 dx
-20 [x4/2 - x3 + 2x2]0x2 dx
[x5/10 - x4/4 + 2x3/3]20 dx
0 - [-32/10 - 4 - 16/3]
= 32/10 + 4 + 16/3
= 188/15
