A thin wire of density pxyyx2 has the shape of a parabola yx

A thin wire of density p(x,y)=y-x+2 has the shape of a parabola, y=x^2 from (-2,4) to (0,0). Set-up an integral to find the mass of the wire.

Solution

Data.

(x,y)= y-x+2

y = x2 (keep in mind for replacing)

boundaries are;

from (-2,4) to (0,0)

--

Answer.

Density mass integral is given by:

m = c (x,y) ds

-200x2 (y-x+2) dydx

-20 [y2/2 - xy + 2y]0x2 dx

-20 [x4/2 - x3 + 2x2]0x2 dx

[x5/10 - x4/4 + 2x3/3]20 dx

0 - [-32/10 - 4 - 16/3]

= 32/10 + 4 + 16/3

= 188/15

A thin wire of density p(x,y)=y-x+2 has the shape of a parabola, y=x^2 from (-2,4) to (0,0). Set-up an integral to find the mass of the wire.SolutionData. (x,y)

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