The frequency distribution represents the commission earned
The frequency distribution represents the commission earned (in dollars) by 100 salespeople employed at several branches of a large chain store
Find the mean. Round the answer to one decimal place.
1. The mean commission is _______
2. The modal class is ____-____ dollars
Thanks, will rate best answer.
| Class Limits | Frequency |
|---|---|
| 150-161 | 18 |
| 162-173 | 9 |
| 174-185 | 15 |
| 186-197 | 21 |
| 198-209 | 17 |
| 210-221 | 13 |
| 222-233 | 7 |
Solution
Class Limits
Frequency
class midpoint
midpoint*frequency
150-161
18
156
2808
162-173
9
168
1512
174-185
15
180
2700
186-197
21
192
4032
198-209
17
204
3468
210-221
13
216
2808
222-233
7
228
1596
sum:
100
sum:
18924
First find the class midpoints by taking the lower class value + the next lower class value and dividing by 2. For example for the first class, (150+162)/2 = 156.
Then multiply each midpoint times the frequency.
Then get the sum of the frequency column and the midpoint*frequency column.
Then divide those sums: 18924/100 = 189.24. This is the mean.
Find the mean. Round the answer to one decimal place.
1. The mean commission is 189.2 (rounded to one decimal place)
2. The modal class is 186-197 dollars (the modal class has the highest frequency.
Thanks, will rate best answer.
| Class Limits | Frequency | class midpoint | midpoint*frequency |
| 150-161 | 18 | 156 | 2808 |
| 162-173 | 9 | 168 | 1512 |
| 174-185 | 15 | 180 | 2700 |
| 186-197 | 21 | 192 | 4032 |
| 198-209 | 17 | 204 | 3468 |
| 210-221 | 13 | 216 | 2808 |
| 222-233 | 7 | 228 | 1596 |
| sum: | 100 | sum: | 18924 |

