Find z such that 224 of the standard normal curve lies betwe

Find z such that 22.4% of the standard normal curve lies between -z and z. A) 0.285 B) 0.070 C) 0.094 D) 0.384

Solution

P(-z1<z<z1)= 0.224

2*P(0<z<z1) = 0.224

P(0<z<z1) = 0.112

P(z<z1) - P(z<0) = 0.112

P(z<z1) = 0.112 + 0.5 = 0.612

P(z<z1) = 0.612

z1 = 0.285