How much water must be added to 20 L of 50 antifreeze soluti

How much water must be added to 20 L of 50% antifreeze solution to reduce it to 40% antifreeze? Let x = the number of liters of water when water is added to this solution, it is 0% antifreeze. Write an equation using 0 + 0.50(20) = 0.40 (x+20) now solve the equation. The answer should be 5L according to my answer sheet.

Solution

Solution: - Let x is the number of liters of water

Hence 0 + 0.5X20 = 0.4 (x +20)

0 + 10 = 0.4 x + 8

0.4x = 10 -8

0.4 x = 2

x = 2/0.4 = 5

Hence x = 5 liters