In the following right triangle find sin A cos A tan A and s

In the following right triangle, find sin A, cos A, tan A, and sin B, cos B, tan B. Please show your work, thanks!

Solution

by pythogorus theorem

AB²=AC²+CB²

(5x)²=x²+CB²

CB²=24x²

CB=(24)x

sin A=BC/AB=^((24)x)/_5x =⁽²⁴⁾/₅

, cos A=AC/AB=^x/_5x =¹/₅

, tan A=BC/AC=^((24)x)/_x =24

and

sin B=AC/AB=^x/_5x =¹/₅

, cos B=BC/AB=^((24)x)/_5x =⁽²⁴⁾/₅

, tan B=AC/BC=^x/_((24)x) =¹/₂₄