A DArsonval moving coil voltmeter with an internal resistanc
A D’Arsonval moving coil voltmeter with an internal resistance of 100 is set to a range of 10V. This voltmeter is connected to a circuit and gives a reading of 5V. This reading is checked with a recently calibrated voltmeter which gives a reading of 5.5V. The implication is that the first voltmeter has an incorrect resistance in series. The meter deflects full scale when 1mA current flows through it. Calculate: (i) The value of the correct series resistance for the 10V range. (ii) The value of the incorrect series resistance.
Solution
Internal Resistance of Meter Ri=100 ohms
Full scale deflection current Ifsd=1mA
(i) V=I(Rse+Ri) where Rse is series Resistance
as V=10 V I=Ifsd=1mA
Rse+Ri=V/I=10/1m=10000 ohms
Rse=10000-Ri=9900 ohms
so correct value of series resistance to be connected is Rse=9900 ohms
(ii) For Voltage value of 5.5 V ,meter reading only 5 V
Current required for 5 V reading is I= Ifsd*5/10 =0.5 mA
But actual voltage applied is 5.5 V
so I= 5.5/(Ri+Rse(incorrect))=0.5 mA
Ri+Rse(incorrect)=5.5/0.5 m=11000 ohms
Rse(incorrect)=11000-Ri=10900 ohms
so incorrect values of series resistance is Rse(incorrect)=10900 ohms
