We want to know whether the diameter of sand grainsX on the
Solution
(a) Yes ,Since if we perform a test H0 : the reression of Y on X is linear H1 : Not H0 .
The test statistics is F,and p-value is 6.48 x 10-5 << 0.05 [ we choose it in general ]
So we reject H0 at 0.05 level of significance and conclude that X determines Y significantly.
(b) The goodness of fitting of the prediction formula is measured by R-square value,
Since it is 0.9104867 . and in general 0< R-square<1 ,and high value of R-square indicates high degree of goodness of fitting, this certainly implies that the prediction is good.
(c)The regression equation is Y= -2.475925 + 17.159369*x
(d) When x= 0.5 ,Y from the above equation is , Y\' = -2.475925 + 17.159369*0.5 = 6.10376 .
(e) The residual for the Y which is actually 5 , but 6.10376 when regressed from the Linear Regression equation is, = 5-6.10376 = -1.10376 .

